What is the tensile strength of a material that fractures with a load of 12300lbs if it has a diameter of .505"?

What is the tensile strength of a material that fractures with a load of 12300lbs if it has a diameter of .505"?

• A. 61400 psi
• B. 60000 psi
• C. 55000 psi
• D. 70000 psi

Answer: (A)

Tensile strength is found by dividing the fracture load by the cross-sectional area of the specimen. For a round bar, area = πd^2/4. With diameter 0.505 in, area ≈ π(0.505)^2/4 ≈ 0.2003 in^2. Then tensile strength = 12,300 lb / 0.2003 in^2 ≈ 61,400 psi. So the material’s tensile strength is about 61,400 psi, which matches the option listing 61,400 psi.

Tensile strength is found by dividing the fracture load by the cross-sectional area of the specimen. For a round bar, area = πd^2/4. With diameter 0.505 in, area ≈ π(0.505)^2/4 ≈ 0.2003 in^2. Then tensile strength = 12,300 lb / 0.2003 in^2 ≈ 61,400 psi. So the material’s tensile strength is about 61,400 psi, which matches the option listing 61,400 psi.